(y+1)/(y^2-y)

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Solution for (y+1)/(y^2-y) equation: 


D( y )

y^2-y = 0

y^2-y = 0

y^2-y = 0

y^2-y = 0

DELTA = (-1)^2-(0*1*4)

DELTA = 1

DELTA > 0

y = (1^(1/2)+1)/(1*2) or y = (1-1^(1/2))/(1*2)

y = 1 or y = 0

y in (-oo:0) U (0:1) U (1:+oo)

(y+1)/(y^2-y) = 0

y^2-y = 0

y*(y-1) = 0

y-1 = 0 // + 1

y = 1

y*(y-1) = 0

(y+1)/(y*(y-1)) = 0

y+1 = 0 // - 1

y = -1

y = -1

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